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Lesson 2 of 22/2 (100%)

Acceleration

If the velocity changes, the object is accelerating. With constant acceleration aa and initial velocity v0v_0, the position after time tt (starting at s=0s = 0) is

s(t)=v0t+at22s(t) = v_0 t + \frac{a t^2}{2}
Two curves of position against time: a parabola for constant acceleration a and a straight line for the same initial velocity without acceleration. Sliders change v0 and a.0246810020406080100120140t (s)s (m)
  • v0 * t + a * t^2 / 2
  • v0 * t
2
1
Show values as a table
t (s)v0 * t + a * t^2 / 2v0 * t
000
12.52
264
310.56
4168
522.510
63012
738.514
84816
958.518
107020
ExerciseDifficulty 2/5

An object starts at s=0s = 0 with v0=1 m/sv_0 = 1\ \text{m/s} and constant acceleration a=6 m/s2a = 6\ \text{m/s}^2. Write an expression for the position s(t)s(t).

Exercise

Which of these are vector quantities (they have a direction)?

Answer options